Inverse Trigonometric Functions
When we introduced the graph of the sine function, we remarked that it repeats every 2π (this corresponds to a full rotation around the circle). Because of this property, the function y = sin(x) is not one-to-one. However, if we restrict the function to the interval [-π/2, π/2], then it is one-to-one. See the figure below.

Figure 1: The unrestricted and restricted sine function
Two notations are commonly used to denote the inverse sine function:
y = sin-1(x) and y = arcsin(x)
WARNING: y
= sin-1(x) is not the same thing as
For example,
|
The graph of sin-1(x) can be found by reflecting the graph of the restricted sine function about the line y = x. Doing so, we have the following graph:

Figure 2: The graph of y = sin-1(x)
Example 1:
Evaluate (i) and (ii)
.
Solution:
(i) is the number in the interval
whose sine is
.
Since
,
we conclude that
.
(ii) is the number in the interval
whose sine is
.
Since
,
we conclude that
.
If f(x) and f
1(x)
are any pair of inverse functions, then by definition,
f[f
1(x)]
= x for every x in the domain of f
1(x)
and
f 1[f(x)] = x for every x in the domain of f(x)
Applying these facts to the restricted sine function and its inverse, we obtain the following two basic identities:
|
sin(sin-1(x)) = x for every x in the interval [-1, 1]
sin-1(sin(x)) = x for every x
in the interval |
The following example indicates that the domain restrictions accompanying these two identities cannot be ignored.
Example 2:
Compute sin-1(sin(π)).
Solution:
Notice that sin(π) = 0, so sin-1(sin(π)) = sin-1(0), but sin-1(0) = 0. Thus, we have that sin-1(sin(π)) = 0, not π. The reason why is because π is not in the domain of the restricted sine function.
We can do the same thing for the cosine function. The graph of cosine repeats every 2π (this corresponds to a full rotation around the circle). Because of this property, the function y = cos(x) is also not one-to-one. However, if we restrict the function to the interval [0, π], then it is one-to-one. See the figure below.

Figure 3: The unrestricted and restricted cosine function
Two notations are commonly used to denote the inverse cosine function:
y = cos-1(x) and y = arccos(x)
WARNING: y = cos-1(x) is not the same thing as
For example,
|
The graph of cos-1(x) can be found by reflecting the graph of the restricted cosine function about the line y = x. Doing so, we have the following graph:

Figure 4: The graph of y = cos-1(x)
Again, we have two basic identities relating the function cos(x) and cos-1(x).
|
cos(cos-1(x)) = x for every x in the interval [-1, 1]
cos-1(cos(x)) = x for every x in the interval [0, π]. |
Example 3:
Evaluate (i) and (ii)
.
Solution:
(i) is the number in the interval [0, π] whose
cosine is 0. Since
,
we conclude that
.
(ii) is the number in the interval [0, π] whose
cosine is
.
Since
,
we conclude that
.
Just as there is a basic identity concerning sin(x) and cos(x), namely sin2(x) + cos2(x) = 1, there is also an identity concerning sin-1(x) and cos-1(x).
|
|
Finally, we introduce the restricted tangent function and inverse tangent function. The graph of cosine repeats every π. Because of this property, the function y = tan(x) is also not one-to-one. However, if we restrict the function to the interval [-π/2, π/2], then it is one-to-one. See the figure below.

Figure 5: The unrestricted and restricted tangent function
Two notations are commonly used to denote the inverse tangent function:
y = tan-1(x) and y = arctan(x)
WARNING: y
= tan-1(x) is not the same thing as
For example,
|
The graph of tan-1(x) can be found by reflecting the graph of the restricted tangent function about the line y = x. Doing so, we have the following graph:

Figure 6: The graph of y = tan-1(x)
Again, we have two basic identities relating the function tan(x) and tan-1(x).
|
tan(tan-1(x)) = x for every real number x
tan-1(tan(x)) = x for every x
in the interval |
Example 4:
Evaluate
(i) and (ii)
.
Solution:
(i) is the number in the interval
whose tangent is -1. Since
,
we conclude that
.
(ii) is the number in the interval
whose tangent is
.
Since
,
we conclude that
.
Example 5:
Simplify the quantity csc(tan-1(x)), where x > 0.
Solution:
We let θ = tan-1(x). That is, we have that tan(θ) = x = x/1. Using this information, we can sketch a right triangle with an angle θ whose tangent is x. See Figure 7.

Figure 7: Graph of θ = tan-1(x)
The Pythagorean
Theorem tells us that the length of the hypotenuse in this triangle is equal to
.
Consequently, we have:
.